# Graphs of Motion

## Practice

### practice problem 1

#### solution

The answers are on the second page of worksheet-compare.pdf.

### practice problem 2

The graph below shows velocity as a function of time for some unknown object.

- What can we say about the motion of this object?
- Plot the corresponding graph of acceleration as a function of time.
- Plot the corresponding graph of displacement as a function of time.

#### solution

The problem presents us with a velocity-time graph. Do not read it as if it was showing you position. You can't immediately determine where the object is from this graph. You can say what direction it's moving, how fast it's going, and whether or not it's accelerating, however. The motion of this object is described for several segments in the graph below.

Acceleration is the rate of change of displacement with time. To find acceleration, calculate the slope in each interval.

Plot these values as a function of time. Since the acceleration is constant within each interval, the new graph should be made entirely of linked horizontal segments.Displacement is the product of velocity and time. To find displacement, calculate the area under each interval.

Find the cumulative areas starting from the origin (given an initial displacement of zero)

00 s → 0 = 0 m 04 s → 0 + 8 = +8 m 08 s → 0 + 8 − 8 = 0 m 12 s → 0 + 8 − 8 − 16 = −16 m 16 s → 0 + 8 − 8 − 16 − 8 = −24 m 20 s → 0 + 8 − 8 − 16 − 8 + 0 = −24 m 24 s → 0 + 8 − 8 − 16 − 8 + 0 + 8 = −16 m 30 s → 0 + 8 − 8 − 16 − 8 + 0 + 8 + 24 = +8 m Plot these values as a function of time. Pay attention to the shape of each segment. When the object is accelerating, the line should be curved.

### practice problem 3

- an object moving with
*constant velocity*. (Let the initial displacement be zero.) - an object moving with
*constant acceleration*. (Let the initial displacement and velocity be zero.)

#### solution

Since the

*velocity is constant*, the displacement-time graph will always be straight, the velocity-time graph will always be horizontal, and the acceleration-time graph will always lie on the horizontal axis. When velocity is positive, the displacement-time graph should have a positive slope. When velocity is negative, the displacement-time graph should have a negative slope. When velocity is zero, the displacement-time graph should be horizontal.Since the

*acceleration is constant*, the displacement-time graph will always be a parabola, the velocity-time graph will always be straight, and the acceleration-time graph will always be horizontal. When acceleration is positive, the velocity-time graph should have a positive slope and the displacement-time graph should bend upward. When acceleration is negative, the velocity-time graph should have a negative slope and the displacement-time graph should bend downward. When acceleration is zero, all three graphs should lie on the horizontal axis.