Discussion

Start with Kirchhoff's circuit law.
Turn it into a first order differential equation.
Rearrange into a form suitable for the separation of variables procedure.
| − RC |
dq |
= q − CV |
| dt |
| |
|
|
| dq |
= − |
dt |
| q − CV |
RC |
|
| − RC |
dq |
= q |
| dt |
| |
|
|
| |
dq |
= − |
dt |
| |
q |
RC |
|
Integrate over the appropriate limits.
| |
q |
|
|
|
t |
|
| |
⌠ ⎮ ⌡ |
dq |
|
= − |
⌠ ⎮ ⌡ |
dt |
| |
q − CV |
RC |
| |
0 |
|
|
|
0 |
|
| ln |
⎛ ⎜ ⎝ |
q − CV |
⎞ ⎟ ⎠ |
= − |
|
t |
| − CV |
RC |
|
| |
q |
|
|
|
t |
|
| |
⌠ ⎮ ⌡ |
dq |
|
= − |
⌠ ⎮ ⌡ |
dt |
| |
q |
RC |
| |
Q0 |
|
|
|
0 |
|
| ln |
⎛ ⎜ ⎝ |
q |
⎞ ⎟ ⎠ |
= − |
|
t |
| Q0 |
RC |
|
Eliminate the logarithm.
Solve for charge as a function of time.
| q = CV |
⎛ ⎜ ⎝ |
1 − e−t/RC |
⎞ ⎟ ⎠ |
|
|
Take the first derivative of charge to get the current.
| I = |
dq |
= |
d |
|
⎡ ⎢ ⎣ |
CV |
⎛ ⎜ ⎝ |
1 − e−t/RC |
⎞⎤ ⎟⎥ ⎠⎦ |
| dt |
dt |
|
| I = |
dq |
= |
d |
Q0e−t/RC |
| dt |
dt |
|
And here it is.