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This problem lends itself well to standard techniques. State the given quantities and convert them to SI units as needed. Solve the appropriate equation of motion to get the acceleration. Substitute this expression into Newton's Second Law and solve. (It can also be solved using the work-energy theorem — as it will be in a later section of this book. Both methods lead to exactly the same answer — as they should.)
| Δs = | 13 km = 13,000 m | v2 = | v02 + 2aΔs | ⇒ |
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| m = | 150 × 106 kg | ||||||||||||||
| v = | 0 m/s | F = | ma = | mv02 | = | (150 × 106 kg)(13.888 … m/s)2 | |||||||||
| v0 = | 50 km | 1000 m | = 13.888 … m/s | 2Δs | 2(13,000 m) | ||||||||||
| 1 h | 3600 s | F = | 11,129 .… N = 11 kN | ||||||||||||
The first sentence of this question came from an article in the Chicago Tribune dated 6 April 2001, "Strait with No Equal Has New Danger." Moral of the story: Yield to the supertanker when you're sailing the Bosphorus.
Answer it.
Answer it.
Answer it.