# Electric Power

## Practice

### practice problem 1

Determine…The electric cycle, 1,825 volts at approximately 7.5 amps for 30 seconds, then 240 volts at approximately 1.5 amps for 60 seconds… a 5 second pause intervenes, and the cycle is repeated, was designed to render the condemned brain dead within the first few moments. The function of the remainder of the cycle is to stop the body's organs so that a physician can certify that death has occurred…

- the total electric energy delivered to Mr. Stewart on the day of his execution.
- his change in temperature assuming assuming a standard 70 kg mass and a body made entirely of water.

#### solution

- Fairly straightforward. Energy is power times time. Electric power is voltage times current. Energy is a scalar, so just add up the parts of the cycle and double each to get the total.
*E*= Σ*Pt*= Σ*VIt**E*= 2[(1825 V)(7.5 A)(30 s)+ (240 V)(1.5 A)(60 s)] *E*= 864,000 J - The electric energy applied to Stewart's body was transformed into heat. Use the sensible heat equation and assume that the human body is basically a bag of water.
*E*=*Q*=*mc*Δ*T*Δ *T*=*Q**mc*Δ *T*=(864,000 J) (70 kg)(4,190 J/kg℃) ∆ *T*≈ 3 ℃

### practice problem 2

Now answer these questions…Most of the energy used to fuel the CCAT house comes from the sun, but a battery bank is also charged with 24 V permanent magnet DC generators run by exercise bikes in the basement. The flywheel on each bike is furnished with a groove. Through this groove is a belt that is attached to the generator's central shaft. The average person pedaling 70 rpm spins the shaft creating an electrical current of 4 A…. This allows someone to get a comfortable workout while at the same time charging the batteries.

- Determine the power output of person pedaling a stationary bicycle at the CCAT house.
- How much work does the person do in one minute?
- Over what total distance have the pedals moved in one minute? (Assume a crank arm length of 18 cm.)
- How fast are the person's feet moving while generating power at the CCAT house?
- With what average force does a typical person in the CCAT house push down on the pedals?

#### solution

- Pick the appropriate electric power equation.
*P*=*VI**P*= (24 V)(4 A)*P*= 96 W - Work is power times time.
*W*=*Pt**W*= (96 W)(60 s)*W*= 5,760 J - This is a geometry problem. In one minute, the pedaler's foot would crank through 70 circumferences.
Δ *s*= 70 × 2π*r*Δ *s*= 140π(0.18 m)Δ *s*= 79 m - This is a basic kinematics problem.
*v*=Δ *s*= 79 m = 1.3 m/s Δ *t*60 s - Use the force–velocity form of the equation for power (
*P̅*=*F̅v*cos θ). Solve it for force. (We need to assume that the force applied by the foot to the crank arm is always parallel to the pedal's velocity.) Insert numbers. Compute solution.*F*=*P*= 96 W = 73 N *v*1.3 m/s

### practice problem 3

- charge in…
- milliamp hours [mAh]
- coulombs [C]

- potential energy in…
- milliwatt hours [mWh]
- joues [J]

Compile your findings in a table like this one.

type | voltage | charge | energy | ||
---|---|---|---|---|---|

(V) | (mAh) | (C) | (mWh) | (J) | |

NiZn | 1.6 | 2500 | |||

NiMH | 1.2 | 2500 |

#### solution

Answer it.

type | voltage | charge | energy | ||
---|---|---|---|---|---|

(V) | (mAh) | (C) | (mWh) | (J) | |

NiZn | 1.6 | 1560 | 5625 | 2500 | 9000 |

NiMH | 1.2 | 2500 | 9000 | 3000 | 10800 |

### practice problem 4

#### solution

Answer it.