Beats

Practice

practice problem 1

A 32.83 ms fragment of the EBS alert tone is shown in the oscilloscope display below. (The full tone lasts 22.5 seconds.) The beat structure is plainly visible at this scale. There are approximately 3.5 cycles of the beat and 29.75 cycles of the carrier visible in the display window. Determine the frequencies of the two tones used to produce the alert.

solution

Start by determining the beat and carrier frquencies from the information given in the description.

fbeat =  3.5 / 0.03283 s  = 107 Hz
fcarrier =  29.75 / 0.03283 s  = 906 Hz

Then work backward to determine the two source frequencies.

fbeat =  f1 − f2  = 107 Hz   f1 − f2  = 107 Hz   f1 = 960 Hz
               
fcarrier =  f1 + f2  = 906 Hz   f1 + f2  = 1812 Hz   f2 = 853 Hz
2  
        2f1  = 1919 Hz    

These are indeed the values specified by the Federal Communications Commission.

practice problem 2

Write something else.

solution

Answer it.

practice problem 3

Write something different.

solution

Answer it.

practice problem 4

Write something completely different.

solution

Answer it.

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